412. Fizz Buzz – Leetcode Solutions

Example 1:

Input: n = 3
Output: ["1","2","Fizz"]

Example 2:

Input: n = 5
Output: ["1","2","Fizz","4","Buzz"]

Example 3:

Input: n = 15
Output: ["1","2","Fizz","4","Buzz","Fizz","7","8","Fizz","Buzz","11","Fizz","13","14","FizzBuzz"]

class Solution:
    def fizzBuzz(self, n: int) -> List[str]:
        # Initialize the result array
        result = []
        
        # Iterate over each number from 1 to n
        for i in range(1, n + 1):
            # Check divisibility conditions
            if i % 3 == 0 and i % 5 == 0:
                result.append("FizzBuzz")
            elif i % 3 == 0:
                result.append("Fizz")
            elif i % 5 == 0:
                result.append("Buzz")
            else:
                result.append(str(i))  # Convert number to string and append
        
        # Return the final result
        return result

class Solution {
public:
    vector<string> fizzBuzz(int n) {
        // Create a vector to store the resulting strings
        vector<string> answer;
        
        // Iterate through numbers from 1 to n
        for (int i = 1; i <= n; ++i) {
            // Check divisibility conditions
            if (i % 3 == 0 && i % 5 == 0) {
                // If divisible by both 3 and 5, append "FizzBuzz"
                answer.push_back("FizzBuzz");
            } else if (i % 3 == 0) {
                // If divisible only by 3, append "Fizz"
                answer.push_back("Fizz");
            } else if (i % 5 == 0) {
                // If divisible only by 5, append "Buzz"
                answer.push_back("Buzz");
            } else {
                // If none of the above conditions are met, append the number as a string
                answer.push_back(to_string(i));
            }
        }
        
        // Return the filled vector
        return answer;
    }
};

var fizzBuzz = function(n) {
    // Initialize an empty array to store the result
    let answer = [];
    
    // Iterate from 1 to n (inclusive)
    for (let i = 1; i <= n; i++) {
        // Check if the current number i is divisible by both 3 and 5
        if (i % 3 === 0 && i % 5 === 0) {
            answer.push("FizzBuzz"); // Add "FizzBuzz" to the result array
        } 
        // Check if the current number i is divisible by 3
        else if (i % 3 === 0) {
            answer.push("Fizz"); // Add "Fizz" to the result array
        } 
        // Check if the current number i is divisible by 5
        else if (i % 5 === 0) {
            answer.push("Buzz"); // Add "Buzz" to the result array
        } 
        // If none of the above conditions are true
        else {
            answer.push(i.toString()); // Convert the number to a string and add it to the result array
        }
    }
    
    // Return the final result array
    return answer;
};

class Solution {
    public List<String> fizzBuzz(int n) {
        // Create a list to store the results
        List<String> result = new ArrayList<>();
        
        // Loop through numbers from 1 to n
        for (int i = 1; i <= n; i++) {
            // Check if the current number is divisible by both 3 and 5
            if (i % 3 == 0 && i % 5 == 0) {
                result.add("FizzBuzz"); // Add "FizzBuzz" to the list
            } 
            // Check if the current number is divisible by 3
            else if (i % 3 == 0) {
                result.add("Fizz"); // Add "Fizz" to the list
            } 
            // Check if the current number is divisible by 5
            else if (i % 5 == 0) {
                result.add("Buzz"); // Add "Buzz" to the list
            } 
            // If none of the above conditions are met
            else {
                result.add(String.valueOf(i)); // Add the number as a string
            }
        }
        
        // Return the resulting list
        return result;
    }
}